7+2[3(x+1)-2(3x-1)]=

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Solution for 7+2[3(x+1)-2(3x-1)]= equation: 


Simplifying
7 + 2[3(x + 1) + -2(3x + -1)] = 0

Reorder the terms:
7 + 2[3(1 + x) + -2(3x + -1)] = 0
7 + 2[(1 * 3 + x * 3) + -2(3x + -1)] = 0
7 + 2[(3 + 3x) + -2(3x + -1)] = 0

Reorder the terms:
7 + 2[3 + 3x + -2(-1 + 3x)] = 0
7 + 2[3 + 3x + (-1 * -2 + 3x * -2)] = 0
7 + 2[3 + 3x + (2 + -6x)] = 0

Reorder the terms:
7 + 2[3 + 2 + 3x + -6x] = 0

Combine like terms: 3 + 2 = 5
7 + 2[5 + 3x + -6x] = 0

Combine like terms: 3x + -6x = -3x
7 + 2[5 + -3x] = 0
7 + [5 * 2 + -3x * 2] = 0
7 + [10 + -6x] = 0

Combine like terms: 7 + 10 = 17
17 + -6x = 0

Solving
17 + -6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-17' to each side of the equation.
17 + -17 + -6x = 0 + -17

Combine like terms: 17 + -17 = 0
0 + -6x = 0 + -17
-6x = 0 + -17

Combine like terms: 0 + -17 = -17
-6x = -17

Divide each side by '-6'.
x = 2.833333333

Simplifying
x = 2.833333333

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